navybratrkd1
navybratrkd1
03-08-2017
Mathematics
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Evaluate ƒ(x) = –x 2 + 1 for x = –3.
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choco4
choco4
03-08-2017
ƒ(x) = –x^2 + 1 for x = –3.
Substitute x for -3
ƒ(x) = –( -3)^ 2 + 1
ƒ(x) = -9 + 1
ƒ(x) = -8
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