Respuesta :

[tex]\begin{gathered} \text{Perimeter of the House become: AB + BC + CD + DE +EF +FA} \\ \text{ 4c + 2 + 4c + 1 + 2c + 3c - 2 + 4c +2 +2c +4c+1 +3c-2 } \\ \text{ collect like terms} \\ \text{ 4c + 4c + 2c +3c +4c +2c +4c + 3c +2 +1-2 +2 +1 -2} \\ \text{ 26c+2} \\ \text{if C= 5, then perimeter becomes: 26(}5\text{) + 2 = 130 + 2 = 132} \\ Perimeter\text{ of Garage: The garage is reactangular in shape: } \\ perimeter\text{ = 2(L + B)} \\ \text{ = 2(}5d+1+3d-2\text{)} \\ \text{ = 2(8d -1)} \end{gathered}[/tex]

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