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Right triangle ABC is shown.

Triangle A B C is shown. Angle A C B is a right angle and angle C B A is 50 degrees. The length of A C is 3 meters, the length of C B is a, and the length of hypotenuse A B is c.

Which equation can be used to solve for c?

sin(50o) = StartFraction 3 Over c EndFraction

sin(50o) = StartFraction c Over 3 EndFraction
cos(50o) = StartFraction c Over 3 EndFraction
cos(50o) = StartFraction 3 Over c EndFraction

Respuesta :

Answer:

sin(50deg) = 3/c

Step-by-step explanation:

akposevictor

Applying the trigonometry ratio, SOH, the equation that can be used to solve for c is: sin (50°) = 3/c.

Trigonometry Ratios

To solve a right triangle, any of the ratios, SOH CAH TOA, can be applied.

Thus, given right triangle ABC, where:

  • angle ACB = right angle
  • angle CBA (∅) = 50 degrees (reference angle)
  • AC = 3 m (opposite)
  • AB (c) = hypotenuse = ?

Apply SOH:

sin ∅ = opp/hyp

  • Substitute

sin (50°) = 3/c

Therefore, applying the trigonometry ratio, SOH, the equation that can be used to solve for c is: sin (50°) = 3/c.

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