let's assume width of a rectangle= a inches than length of the rectangle = 2*a + 2 = 2a+ 2 inches perimeter of the rectangle. = 70 inches
perimeter (P) = 2(length+ width) after substituting value of l and w we have p = 2(l+w) 70= 2( 2a+2+ a) 70= 2(3a+2) 70= 6a+4 70 - 4= 6a 66= 6a, a= 66/6= 11 so a=11 inches, a= width therefore width is = 11 inches length is = 11*2+2= 24 inches